dynamics meriam 6th edition solution
tangent to the path with magnitude 5 m/s, \( v_x = v \times \frac{dx}{ds} \), \( v_y = v \times \frac{dy}{ds} \). Using the chain rule, \( ds = \sqrt{1 + (dy/dx)^2} \, dx \). At \( x=1 \), \( ds/dx = \sqrt{1 + 8^2} = \sqrt{1 + 64} = \sqrt{65} \). Therefore, \( v_x = 5
